10 football teams compete in a round-robin tournament (each team plays exactly once against every other team). Thus for a league of n teams, each team playing two number of teams is even, each team gets paired with . The total points are accumulated to decide the ranks of the teams.
Teams get three points for everyone and one point for every time. Solution The correct option is C The probability that A wins and loses equal number of matches is 17 81 Probability of equal number of Draw (D), win (W) and loss (L). In a football tournament, a team T has to play with each of where each team plays every other team exactly once. B will play a match with C (B has already played a match with A) C has already played matches with team A and B.
Let N = number of teams in the tournament. All other teams (5) have a combined score of 28 – 18 = 10 points.
In A Football Tournament Each Team Plays Exactly 19 Matches Teams Get 3 Pointsgames Teams get 3 points for every win and 1 point for every tie.
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